Second Derivative of this function Calculate the higher derivative. f(x) = 5 x sin 5 x f′′(x) = I typed in a ton for answers for this problem and still no luck. Also could not figure out this problem
Use the product rule. f'(x)=first times derivative of the second + second times derivative of the first.
would f(x)= 5x? or xsin(5x)?
Well, in your original post you state \[f(x)=5x \times \sin (5x)\]
\[f \prime(x)=5x (\cos 5x)\times 5 + \sin5x \times 5\] Simplified is \[25x \cos5x+5\sin5x\]
oh ok that for the f′′(x) = -125xsin(5x)+25cos(5x)?
*then*
Yes, but don't for get the second part ... the 5sin5x
Should that be an addition to my answer or correcting a part?
In addition to. You found the second derivative of the 25xcos5x, but not the 5sin5x.
so f(x)′′=−125xsin(5x)+25cos(5x)+5sin(5x)
No. The derivatve of 5sin(5x) is 5cos(5x)*5, so 25cos(5x).
f′′(x) = -125xsin(5x)+25cos(5x)+25cos(5x)
Oh wow thanks, to many numbers get me confused lol, did you know how to do any of the attach files by chance?
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