Question

would this be 1-1(x+9) or 1-1(x-9)? or something else completely??

Answer 1

when adding fractions:
cross multiply the denominators
then add the numerators (u can only add 2 numerators together if they have a common denominator)

so times the 1/x by x-9 top and bottom
1 ---> 1(x-9) = x-9
---- -------- = -----
x ---> x(x-9) = x(x-9)

then do the same with the 1/(x - 9) fraction

1 ---> 1 (x) = x
----- ------ = ---------
x-9 ---> x(x-9) = x(x-9)

Answer 2

so now just add the numerators (top numbers) together
(as we have common denominator)
\[\frac {x-9}{x(x-9)} - \frac {x}{x(x-9)} = \frac {x -9 - x}{x(x-9)} \]

Answer 3

= ??? @4sodapop ??

Answer 4

just a side note:

so times the 1/x by (x-9) top and bottom
1 ---> 1 times (x-9) = x-9
---- -------- = -----
x ---> x times (x-9) = x(x-9)

then do the same with the 1/(x - 9) (this time multiply top and bottom by x) fraction

1 ---> 1 times (x) = x
----- ------ = ---------
x-9 ---> (x-9) times x = x(x-9)

Answer 5

whatttt

Answer 6

need common base to add fractions

so 1/7 + 2/8 .... cant just add the 1's

need common base
so times the 1/7 by 8 (top and bottom) and you get 8/56
then times the 2/8 by 7 (top and bottom) and you get 14/56

now: 8/56 + 14/56 = 22/56 (you can just add the 8 and the 14 now, same base of 56)

so same principal above

Answer 7

but do you switch the signs??

Answer 8

@Jack1

Answer 9

no... the equation stays the same

so 1/x - 1/y = ???/xy

= y/xy - x/xy = (y - x) /xy

Answer 10

did i make a mistake with the signs somewhere above...?
if so im sorry
but your original eqn was :
1/x - 1/(x-9) = ??? / x(x-9)

so equates to
x-9/x(x-9) - x/ x(x-9) = x-9-x/x(x-9)
= -9/x(x-9)

is that right @4sodapop ...?

Answer 11

awwww... SH*7, sorry, ur right, ur original equation was x+9.... not x-9....
my complete bad, i've just muddied the waters completely

so should be:
but your original eqn was :
1/x - 1/(x+9) = ??? / x(x+9)

so equates to
x+9/x(x+9) - x/ x(x+9) = x+9-x/x(x+9)
= 9/x(x+9)