Question

what is the derivative of x^2 sin 8x

Answer 1

2xsin8x+8x^2cos8x

Answer 2

use the product rule...

Answer 3

Where does the 8x^2 in the second part of the problem come from?

Answer 4

dsin8x is 8 cos8x multiplied by x^2 is second term

Answer 5

Okay, I understand now. Thank you for your time. :)

Answer 6

dsin8x= cos8x d8x=cos8x 8 dx

Answer 7

\[h(x) = f(x)g(x)\\h'(x) = f'(x)g(x)+f(x)g'(x)\]

Answer 8

start with the 2 functions that are the factors of the whole function

\[f(x) = x^2...... then....... f'(x) = 2x\]

and

\[g(x) = \sin(8x).... then..... g'(x) = 8\cos(8x)\]

so the product rule says

y' =f(x)*g'(x) + g(x)*f'(x)

hope this helps