Question

Probability Question:

A box contains 8 tickets bearing numbers 1,2,3,4,5,6,8,10. One ticket is drawn and kept aside. Then a second ticket is drawn. What's the probability that both tickets show even numbers?

Answer 1

Did you know that the probability of 2 consecutive events is the product of the probabilities of each separate event?

Answer 2

yes
plz reply

Answer 3

plz tell dear

Answer 4

Alright so what is the probability of getting an even ticket in the first pull? Then, since you will only have 7 tickets left(the one pulled is put aside), what is the probability of getting another even ticket? Multiply them together.

Answer 5

1/8 X 1/7 = 0.125 X 0.1428 = 0.1785

Answer 6

is it correct?

Answer 7

Not quite. Since you need even tickets, how many even tickets do you have?

Answer 8

5 sir

Answer 9

4

Answer 10

Ok list all the even tickets.

Answer 11

2,4,6,8,10

Answer 12

So that's 5. Probability should be 5/8 for the first one. Second one?

Answer 13

plz tell

Answer 14

its mean answer is 5/8 x 4/8 =0.3125

Answer 15

Well when you pull out an even ticket you will have one less even ticket and one less total ticket. You were almost there last time but you forgot there was more than 1 even ticket

Answer 16

plz explain in detail

Answer 17

So when you pull out the first ticket, your prob. of getting an even one is 5/8. After that, you keep it aside and will have 1 less. So it should be 4/7

Answer 18

Is it correct to write=
P(AnB)= P(A) X P(B) = 5/8 X 4/7

Answer 19

Right. I'm not used to using the notations but I believe so.

Answer 20

Thanks a lot dear
my pleasure to have friend like u

Answer 21

You're welcome. The pleasure is mine to help someone learn.

Answer 22

Please close the question when you are done though.