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MEDAL REWARDED Find the inverse of the function. cuberoot x/6 -7
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@John_ES
As we have, \[y=\sqrt[3]{x/6-7}\]Change x and y, \[x=\sqrt[3]{y/6-7}\]Then solve for y, \[x^3={y/6-7}\Rightarrow y=6x^3+42\]And that is the inverse.
These are my answer choices: f-1(x) = 6(x+7)3 f-1(x) = 6(x3 + 7) f-1(x) = 18(x + 7) f-1(x) = [6(x+7)]3
@John_ES
Then it's the second, \[f^{-1}(x)=6x^3+42=6(x^3+7)\]
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