Could someone walk me through the steps of balancing this equation:
C6H6+02--- CO2 +H20

Question

Could someone walk me through the steps of balancing this equation:
C6H6+02---> CO2 +H20

anonymous · Answer

its simple friend 
2C6H6+9O2->12Co2+6H2o
ok

anonymous · Answer

Could you show me the steps...Because I know how to do it, but the part with the oxygen throws me off

anonymous · Answer

Because there is two oxygen's on one side, and I never know how to get it to balance.

joannablackwelder · Answer

I would first make the coefficient of CO2 6 to balance the carbons, and 3 in front of the H2O to balance the Hydrogens.

joannablackwelder · Answer

But not the number of O's on the right side is odd (15), which you cant make with whole number coefficients on the right. So, put a 2 in font of the C2H6, Which means you will need to double the number of CO2s and H2Os. Now the Oxygens on the right are an even number.

joannablackwelder · Answer

I get the coeffficient of O2 to be 15.

anonymous · Answer

Thanks...I'm still a little confused. I get the problems that are like:H2+02-->H20, Because they don't double up on everything.

joannablackwelder · Answer

Did you understand how to get to the step
C6H6 + O2 -> 6CO2 + 3H2O?
(Not fully balanced)

joannablackwelder · Answer

You need to have the same number of each element on each side of the reaction (mass cannot be created or destroyed)