Question

3^2b^2c^-4
times
3^-1b^-5c^7
as a fraction

Answer 1

\[\large3^2b^2c^{-4}\times 3^{-1}b^{-5}c^7\]
\[=\huge 3^{2-1}b^{2-5}c^{-4+7}\]

Answer 2

how would it look like as a fraction?

Answer 3

you should get
\[\large 3b^{-3}c^3\]

Answer 4

if you have to write with positive exponents, note that
\[b^{-n}=\frac{1}{b^n}\] and so
\[b^{-3}=\frac{1}{b^3}\] making your answer
\[\large \frac{3c^3}{b^3}\]