Question

Calc Trig question

Answer 1

Do you have any thoughts as to how to proceed?

Answer 2

Hmm... not quite how I would proceed. I would use some u substitution.

Answer 3

\(\displaystyle \frac{d}{dx}=\sec^8(5x^2+2)=\frac{du^8}{du}\frac{du}{dx}\;~\text{where}~u=\sec(5x^2+2)\&\frac{d}{du}(u^8)=8u^7\)

This is how I would proceed. But if you haven't been taught substitution...

Answer 4

That should be,

\(\displaystyle \frac{d}{dx}(\sec^8(5x^2+2))\)

oopsies, notation is everything.

Answer 5

@FutureMathProfessor
Would you care to help this gentleman with his question?
I am a bit rusty in his method that is expected.