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Mathematics 6 Online
OpenStudy (anonymous):

Find the values of k that make 2x^2 + kx + 5 factorable. A. 1 or 10 B. 2 or 5 C. 7 or 11 D. 1 or 5

OpenStudy (***[isuru]***):

to make x factorable.. the discriminant of "x" should be higher than 0 and should be a perfect square... the discriminant of a function ax^2 + bx + c is b^2 - 4ac so... ur prob 2x^2 + kx + 5 ax ^2 + bx + c the discriminant is.. b^2 - 4ac k^2 -40 and this value should be above 0 which means.. k^2 - 40 > 0 k^2> 0 and k^2 - 40 should be a perfect square.... the choices that satisfy this conditions r.. 7 , 11 hope this will help ya!!!

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