Suppose that an account earns 5.3% interest and after 3 years the balance is 6954$.Find the principle that was invested.Use the formula B=P+Prt,which is used to calculate the balance in an account if simple interest is added to a principle P at an interest rate of r after t years.
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OpenStudy (anonymous):
@help123please.
OpenStudy (anonymous):
@hba
OpenStudy (anonymous):
I seriously need help
OpenStudy (anonymous):
@shamil98
OpenStudy (anonymous):
@mathstudent55
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OpenStudy (shamil98):
Would you not just plug in the given values? try doing the equation.
OpenStudy (anonymous):
okay 6954=P+P(5.3/100)(3)
OpenStudy (anonymous):
Am i correct so far?
OpenStudy (jdoe0001):
\(\bf Balance = Principal + Principal \times rate \times time\\
B = P + Prt\\
r = \textit{rate in decimals, 5.3\%} = \frac{5.3}{100}=0.053\\
t = \textit{time in years, in this case } \quad 3\\
B = \textit{the balance in the account, well, today's balance is}\quad \$6,954\\ \quad \\
B = P + Prt\implies 6954= p + p \times 0.053 \times 3\)
solve for "p"
OpenStudy (shamil98):
6954 = P + (5.3(3)p)
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OpenStudy (shamil98):
yeah solve for p, my input was incorrect , 5.3% interest in decimal is actually 0.53
OpenStudy (anonymous):
i got 43735.84....
OpenStudy (anonymous):
is this right
OpenStudy (shamil98):
0.053* my bad ._.
OpenStudy (anonymous):
i still got this answer
i know im wrong but i dont know what i did wrong
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OpenStudy (anonymous):
hba help
OpenStudy (shamil98):
6954=p+p×0.053×3
6954 = 2p x 0.159
6954 = 0.318p
p = 21867.9245283