Question

Using complete sentences, explain how to convert your birthday function into standard form. Ok here is the birthday function: y= 2(x-3)^2 + 6 help please O.O

Answer 1

Holy pellet.

Answer 2

standard form is
y = ax^2 + bx +c

to get that form, multiply (x-3)(x-3) (use FOIL if you know it),
as a first step. can you do that ?

Answer 3

yes thank you

Answer 4

what did you get ?

Answer 5

y= 4x^2 – 12x - 3 is this right?

Answer 6

First, what is (x-3)(x-3) ?
can you do that ?

Answer 7

x^2 -3x - 3x - 9

Answer 8

+9 my bad

Answer 9

yes, and -3x - 3x can be combined into -6x (you have -3 x's and take away another 3 x's to get -6 x's)

that means you now have
2(x^2 -6x + 9) +6

the next step is "distribute" the 2. that means multiply 2 times each term inside the parens

Answer 10

2x^2 -12x +18 +6; so that would give you 2x^2 - 12x +24?

Answer 11

yes, the last +18+6 can be combined to get +24
so this quadratic in standard form is 2x^2 - 12x +24

Answer 12

awesome. thank you:)

Answer 13

Create two additional quadratic functions, g(x) and h(x).
A. The function g(x) will open the same direction as f(x), have the same vertex, but will be narrower
what does it mean by narrower? @phi

Answer 14

they want you to use the "vertex" form of a quadratic... (also known as a parabola when you graph it)

vertex form is:
y = a(x-h)^2+k , where (h,k) is the vertex.

the "a" controls how fat or skinny the parabola is

Answer 15

Here is an example I made using geogebra... free software you can download.. see geogebra.org