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Limit when x->2 (x-2)/(sqrt(x^2-3)-(x/2))
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use L'hopitals rule
differentiate numerator: (1/2)(1/Sqrt[x+2])
That's the problem, the task is "solve WITHOUT usin l'Hopitals" :/
differentiate denominator: 1
oh okay :)
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limit becomes: (1/2)(1/Sqrt[7+2]) = 1/2(1/3) = 1/6
I think I'm supposed to do it something like this:
where you multiply the denominator and nominator so as to get a (x-2) both above and below the line. I just can't seem to get there :P
@***[ISURU]***
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