2 C4H10(g) + 13 O2(g) -- 8 CO2(g) +10 H2O(g) is balanced. How do i Calculate the moles of CO2 produced when 2.65 moles of C4H10 are allowed to react with 13.06 moles of O2 how do i Do this? Whats the answer?

Question

2 C4H10(g) + 13 O2(g) --> 8 CO2(g) +10 H2O(g) is balanced. How do i Calculate the moles of CO2 produced when 2.65 moles of C4H10 are allowed to react with 13.06 moles of O2 how do i Do this? Whats the answer?

joannablackwelder · Answer

Start by finding the limiting reactant. 2.65 moles C4H10 (1 reaction/2 moles C2H10) = 1.325 reactions. 13.06 moles O2 (1 reaction/13 moles of O2) = 1.005 reactions. The one that makes less reactions happen is the limiting reactant.

joannablackwelder · Answer

Then you calculate the number of moles based on the moles of O2.
13.06 moles O2 (8 moles CO2/13 moles O2) = 8.04 moles CO2.

anonymous · Answer

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joannablackwelder · Answer

:)

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joannablackwelder · Answer

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anonymous · Answer

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