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Mathematics 21 Online
OpenStudy (anonymous):

find a

OpenStudy (anonymous):

\[y = \frac{ 3(a-2) }{ 1-b }\]

OpenStudy (anonymous):

y=3a-6/1-b

OpenStudy (agent0smith):

Mutltiply both sides by (1-b) first.

OpenStudy (anonymous):

multiply? ummm can u show?

OpenStudy (agent0smith):

\[\Large y(1-b) = \frac{ 3(a-2) }{ (1-b) }* (1-b)\]

OpenStudy (anonymous):

;/ i still dont get it ;/

OpenStudy (agent0smith):

We're trying to find a... that's the first step, cancel off the 1-b.

OpenStudy (agent0smith):

We want to get a alone.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

y=3a-6/1-b y(1-b)=3a-6/1-b(1-b) y-b=3a-6

OpenStudy (agent0smith):

^you should def use latex and not write math that way...

OpenStudy (anonymous):

I meant y-yb=3a-6

OpenStudy (anonymous):

\[y-yb=3a-6\]

OpenStudy (anonymous):

haha is that a little clearer^

OpenStudy (agent0smith):

y(1-b)=3a-6/1-b(1-b) that's the part that you really need to write in latex (the way i already did :P )

OpenStudy (anonymous):

its all the same... just harder to see it the way i wrote it

OpenStudy (agent0smith):

^very hard to see because it's not clear w/o brackets\[\Large y(1-b) = \frac{ 3(a-2) }{ (1-b) }* (1-b)\] the 1-b on the right cancels off \[\Large y(1-b) = 3(a-2)\] now you can distribute as @hello1213 did

OpenStudy (anonymous):

y is it y(1-b) at the beginning?

OpenStudy (anonymous):

multiply both sides by 1-b

OpenStudy (agent0smith):

Mutltiply both sides by (1-b) first. < my first post :P

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