Okay, so some somehow I am just completely stuck this question. This is one of the examples from my textbook that I just can't solve and would probably help me solve the others I'm stuck on. Solving by Substitution 3x+4y=12 2x+y=10 I keep getting this: 3x+4(-2x+10)=12 3x-8x+40 -5x+40=12 -5x=-32 x=6.4 Am I missing something staring me in the face? Because the answer should be x=5.6
Are you studying slopes and linear functions and stuff?
Because to me that looks lie the standard form of a linear function, which is Ax - By = C.
Well, it's in the Linear Systems Chapter under Solving Systems Algebraically.
I should note, this is Algebra 2 if that helps.
Okay then. I think what they mean is to find x first then y. This is how you do it!:\[3x+4y=12\]\[3x+4(0)=12\]\[3x=12\]\[12\div3=x\]\[4=x\]Now, you are not finished yet. All you have to do next is put it in a coordinate plane thingie: (4, 0). Now - did you see what I did with the y? I just made it zero. Do the same thing with x, when finding y. Try to do it yourself! :-)
And OMG, Algebra II. I am in Algebra I, but I just finished a chapter called "Linear Functions". But I guess it would also be linear systems because I also learned linear models, linear equations, etc...
Please tell me when you are done.
...Or if you need assistance.
I'll tell you what to do after you solve for y.
Doing it on some paper, just a sec.
Okay, well I see what you're saying but this is a textbook example, and it is telling me that x=5.6, and somehow I've manged to get x=6.4 and x=-1.6 the two times I solved it. Haven't even gotten to y yet. That is the whole issue.
Hm. So x HAS to equal 5.6? Well, if x = 5.6, can't you plug in 5.6 and then solve for y? Or is 5.6 the answer?
5.6 is x which I then need to use to find y, I think I see where I went wrong so I'm going to try again real quick.
Okay. :-)
Figured out where I went wrong, 12-40=-28, not 32. Makes a big difference and 4*10 does not =4. Moment of stupidity. Got it now, thanks for the help lol.
Okay, you are welcome. :-D
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