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OpenStudy (anonymous):
Here it is :)
OpenStudy (anonymous):
@goformit100 @shamil98
OpenStudy (anonymous):
@satellite73 Please help , thanks so much :))
OpenStudy (anonymous):
@Preetha @Zarkon
OpenStudy (anonymous):
@SithsAndGiggles
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OpenStudy (anonymous):
@agent0smith
OpenStudy (anonymous):
Please help :(
OpenStudy (anonymous):
@e.cociuba @nincompoop
OpenStudy (anonymous):
Simple example for an equation with extraneous solution: \(\sqrt x=-1\).
Squaring both sides gives you \(x=1\); however, \(\sqrt1\not=-1\).
OpenStudy (anonymous):
@SithsAndGiggles What do I say to explain the steps? btw thanks so much :)
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OpenStudy (anonymous):
"Squaring both sides" is a step.
OpenStudy (anonymous):
@SithsAndGiggles Thanks alot :))), I just gave you a medal :)
OpenStudy (anonymous):
@SithsAndGiggles What would be an example for non-extraneous solution?
OpenStudy (anonymous):
Btw, you should probably explain why \(x=1\) is not a solution to the first example.
For a non-extraneous solution, \(\sqrt x=1\) is a pretty simple example.
OpenStudy (anonymous):
@SithsAndGiggles Again, thanks so much for the help :)
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