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derivative problem: f(x)= sec(x^2) find f'(sqrt(pi/4)) can someone explain how to do this?
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The derivative of sec(x) is sec(x)tan(x) Because it's sec(x^2) you use the chain rule to get the derivative as: f'(x)=sec(x^2)tan(x^2) times (2x) Then you plug in sqrt(pi/4) everywhere there's an x to find your answer.
How come you have to multiply the sec(x^2)tan(x^2) by the derivative of x^2 ?
The chain rule for derivation.
For example: if f(x) = (2x)^5 2x is also a function and will need to be taken the derivative of. f'(x) = 5(2x)^4 * (2) 5(2x)^4 because of the power rule of derivatives, and 2 because that's the derivative of the inner function.
okay thank you so much!
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