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Determin the period and amplitude of the following function. y=4 cos(3x/4+pi/4)
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i really just need the period
(3x/4+pi/4) is bound between 0 and 2pi 0< 3x/4+pi/4 < 2pi solve inequality (subtract pi/4 from all three portions, multiply by 4/3 to all three sections to get x by itselfP the difference between your large value on the right and the small value on the left is your period.
-pi/4 < x < 7pi/4 7pi/4 -(-pi/4) = 8pi/4 = 2pi
so it would be 8/3--pi/3
-pi/4 < x < 7pi/4 7pi/4 -(-pi/4) = 8pi/4 = 2pi
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8pi/4 = 2pi
=period
the cos function would start at -pi/4 and end at 7pi/4 for a period length of 2pi
okaay
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