How does:
((sin(x))(1/x)-(ln(x))(cos(x))/(sin^2(x))
equal:
((sin(x))-(x)ln(x)(cos(x)))/((x)sin^2(x))

How are there more x's in the final answer?

Question

How does:
((sin(x))(1/x)-(ln(x))(cos(x))/(sin^2(x))
equal:
((sin(x))-(x)ln(x)(cos(x)))/((x)sin^2(x))

How are there more x's in the final answer?

zepdrix · Answer

$$\Large \frac{\left(\frac{\sin x}{x}-\ln x \cos x\right)}{\sin^2x}\quad=\quad \frac{\left(\frac{\sin x}{x}-\frac{x \ln x \cos x}{x}\right)}{\sin^2x}$$

zepdrix · Answer

Get a common denominator, see how that works? :)

zepdrix · Answer

$$\Large =\frac{\left(\frac{\sin x-x \ln x \cos x}{x}\right)}{\sin^2x}\quad=\quad\frac{\sin x - x \ln x \cos x}{x \sin^2x}$$

anonymous · Answer

Thanks! :)

zepdrix · Answer

c: