(a) If 32123°=360n°+θ , where n is an integer and 0°

Question

(a) If 32123°=360n°+θ , where n is an integer and 0°<θ<360°, find the values of n and θ.
(b) Using the result of (a), express tan32123° in terms of acute angle.

@hartnn @ganeshie8

hartnn · Answer

say we have 500 = 360n +x 
so, since x can be between 0 to 360 
we have to first go 1 full round till 360 and check how many degrees remain to get to 500 
so, here n=1, 
and x = 500-360*1
got this ?

anonymous · Answer

wow, yes

hartnn · Answer

so try with 32123 now ?

hartnn · Answer

hint, i got n=1 in 500 by dividing 500 by 360 and ignoring the decimal part

anonymous · Answer

≈89.23055555....
=89

anonymous · Answer

corr. to 2 sig fig
lol

hartnn · Answer

correct! 89 :)

hartnn · Answer

so theta will be just 32123 - 360*89

anonymous · Answer

83?

hartnn · Answer

yup, correct :)
so angle 32123 is equivalent to angle 83

hartnn · Answer

like sin 32123 = sin 83, cos32123 = cos 83
and so on...

anonymous · Answer

oh i see
than you very much:)
would you kindly help me with other questions?

hartnn · Answer

so part b) will be tan32123 = tan 83
and yes, sure...i have like 10 min more