Question

Find the absolute maximum and absolute minimum values of f on the given interval. f(x)=x^3-9x^2; [0,10]

Answer 1

is this calculus?
if so, find the first derivative

Answer 2

yes this calculus

Answer 3

so find the first derivative

Answer 4

can u do it?

Answer 5

not really it takes me a mintue

Answer 6

@vjydubey I cant read the outcome

Answer 7

in this case u have to follow two simple rules
\[ (u\pm v)'=u'\pm v' \]
\[ (x^n)'=n\cdot x^{n-1} \]

Answer 8

okay..follow steps
1) find critical points of curve and check whther they are local maxima or minima
2)evalute function at that point
3)also evalut them at boundries for maximums which are not maxima

Answer 9

so, since
\[ f(x)=x^3-9x^2 \]
then
\[ f'(x)=(x^3)'-(9x^2)'=3x^2-9(2x)=3x^2-18x \]

Answer 10

@helder_edwin what numbers go where... im confuse

Answer 11

okay okay im following you

Answer 12

sorry, this web site is acting weird

Answer 13

at least from my end.

Answer 14

once you have the first derivative, you solve the equation
\[ y'=0 \]

Answer 15

so now we solve
\[ 0=f'(x)=3x^2-18x=3x(x-6) \]
from which we have that x=0 or x=6

Answer 16

both solutions lie in the interval given

Answer 17

got it, so far?

Answer 18

yes I solved it

Answer 19

great