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Physics 13 Online
OpenStudy (anonymous):

A ball is thrown vertically upward with a velocity of 98 m/s, how high does the ball rise? (g = 9.8 m/s -2 ) @JFraser I want to show you my work then you tell me that I'm correct or not ..

OpenStudy (jfraser):

i've got my answer, what have you got?

OpenStudy (anonymous):

sorry disconnected ..

OpenStudy (anonymous):

i got 490 meters ..I put this 1/2mv^2 = mgh h = 2v^2/g

OpenStudy (anonymous):

ops 1/2v^2/g

OpenStudy (anonymous):

it is equal to Height ...Am I do this correctly ??

OpenStudy (anonymous):

are u there @JFraser ?

OpenStudy (jfraser):

that's what i get, also

OpenStudy (jfraser):

i used \[V_f^2 = V_i^2 - 2g\Delta x\]

OpenStudy (anonymous):

what is value of Vf ??? zero ???

OpenStudy (jfraser):

exactly, because it decelerates on the way up, and at the max height, its velocity is zero

OpenStudy (jfraser):

i'm leaving to get dinner, so if you have anything else it'll have to wait for someone else

OpenStudy (anonymous):

ok ty so much ..I am tagging you in another problem too ..you answer there whenever you 'll free . I am also signing out now .thanks again :)

OpenStudy (gtxmuqsit):

490 meters is correct answer \[v ^{2}/2g=h\]

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