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Chemistry 19 Online
OpenStudy (anonymous):

What will be the new volume of a 250 mL sample of gas at 300 K and 1 atm if heated to 350 K at 1 atm? Law used:

OpenStudy (anonymous):

Looks like you are working with the equation (P1V1)/(T) = (P2V2)/(T2). Since the pressure stays the same, it is reduced to V1/T1 = V2/T2. So, 250/300 = V2/350 or V2=(250 * 350)/300 = 291.66mL. Charles' Law.

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