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The function s=f(t) gives the position of a body moving on a coordinate line, with s in meters and t in seconds. s= -t^3 + 6t^2 - 6t, 0 less than or equal to t less than or equal to zero. Find the body's speed, velocity and acceleration at t=6 seconds.
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rate of change
to get the rate of change find the 1st derivative.. it will give the rate of change
so the first derivative would be -3t^2 + 12t - 6?
thats it, to find the instantaneous rate of change at some point, just substitute a value.
the acceleration will be t=6 seconds. so will it be -3(6)^2 + 12(6) -6?
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