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Mathematics 9 Online
OpenStudy (anonymous):

simlify http://media.education2020.com/evresources/2003-01-05-00-00_files/i0130000.jpg

OpenStudy (anonymous):

thinking 8.5

OpenStudy (anonymous):

i have A. 14n+ 1/2 B. -n+2 C. n+2/3 D. 5n-3

OpenStudy (anonymous):

uM I THINK IT MIGHT BE C

OpenStudy (anonymous):

thanks :)

OpenStudy (austinl):

Ok, we have, \(\displaystyle \frac{8n+3-6n}{2}\) Which can be written as, \(\displaystyle \frac{8n-6n+3}{2}\Leftrightarrow~\frac{(8-6)n+3}{2}\) Which when simplified is, \(\displaystyle \frac{2n+3}{2}\) Then we can apply some rules of fractions, \(\displaystyle \frac{2n}{2}+\frac{3}{2}\) Can you simplify that?

OpenStudy (anonymous):

Ohh Lorrhddd

OpenStudy (anonymous):

would it be D?

OpenStudy (anonymous):

idk if i did that right tho

OpenStudy (austinl):

\(\displaystyle \frac{2n}{2}\Leftrightarrow \frac{2\times n}{2}\) Can anything be simplified from this?

OpenStudy (anonymous):

B? -n+ 2?

OpenStudy (austinl):

One more try with this... \(\displaystyle \frac{2n}{2}=\frac{2}{2}\times n=~?\)

OpenStudy (anonymous):

oh I get it now

OpenStudy (austinl):

lol, she left... If you care, \(\displaystyle \color{red}{\frac{2n}{2}}+\color{blue}{\frac{3}{2}}\) Simplifies down to, \(\displaystyle \color{red}{n}+\color{blue}{\frac{3}{2}}\)

OpenStudy (anonymous):

that makes more sence thanks :)

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