use additive inverse to solve 3x+25=56 what do you do first
Subtract a constant from both sides to start getting x by itself. Or another way to put it is add the opposite of the constant.
3x+25=56 -25 -25 3x=31 x=31/3
my answer choices are a- add 25 to both sides b- add -25 to both sides c- add 3 to both sides d-add -3 to both sides
so what would my answer be
B
What's the opposite of the constant?
i really dont know
Do you know what a constant is?
no
a constant is a number on its own
OK, then we need to start there. A constant is a number that is what it is. There's nothing changing it. It's constantly the same. A variable is a number that is having something done to it. Like 3x. 3x isn't a 3. It's a 3 times something else. What it really is depends on what that x is. If x is 2, then it's a 6. If x is 3, then it's a 9. It varies, hence variable.
ok so how is the answer b if 56 - 25 is 31 and 56 + 25 is 81
so you -25 to the 56 because your trying to get the x by itself so your subtracting the constant that's on the same side of the variable. the answer is b.
Because of what the question is asking you. It's asking you what you do FIRST, not what the result of doing it is.
ok so you add negative 25 first
Exactly. Because your goal is to get anything with x in it on one side and the constants on the other side.
yes to the 53
ok thanks can yall help me out somemore please witt a couple other problems
Sure.
sure
how do i solve this inequality \[15 <5 - 2 \left( 4m \+7)\]
15< 5 - 2 (4m+7)
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