A security system requires a five-digit passcode where each digit can be any number from 1 to 9. How many possible passcodes can there be?
Are you familiar with permutations?
partially I know this equation c(n,r)=n!/(n-r)!r!
There are 15 employees that must attend training sessions where only 3 people can be trained at a time. How many different possible groups are there?
Yes use that formula. For your next questions you do not care for the arrangement as long as you have groupings, so you will use combinations.
ok so would it be 15!/(15-3)!3! ?
Correct.
The permutations for P, R, and Q are:
P, R, Q as the elements? What do you think?
(PRQ), (PQR), (RPQ), (QPR), (QRP), (RQP)
Correct. You you can also use the permutations formula.
ok thanks There are 12,000 boys at a university of 28,000 people. If someone randomly knocks on a dorm room door, what are the odds that he will meet a girl? for this on do I use the formula?
No this is probability. You want the probability of knocking a girl's door.
so I divide them and I get 2/3?
What do you mean by divide? You are given the number of boys. If you just take that value you will be calculating the probability of knocking a boy's door :)
so 3/7?
How did you get that value?
I don't really understand what you meant so I did 12,000/28000
Like I said, 12000 is the number of boys. If you use that value what you get is the probability for a boy's door.
The Fundamental Counting Principle is the most useful for describing:
combinations?
Not sure I think permutations. You should Google it
The Fundamental Counting Principle is the most useful for describing:
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