find the value of the discriminant and describe the number and type of roots x^2+5x+6=0

Question

mertsj · Answer

What does it mean by discriminant?

anonymous · Answer

what do you mean? im honestly not sure it just gave me problems n answers to choose from since the darn powerpoint wont come up

mertsj · Answer

That is your problem.  Type "discriminant of quadratic equation" into a search bar and find out what it is.

anonymous · Answer

For a given quadratic $ax^2+bx+c$, the discriminant is $b^2-4ac$.

If it's positive, then you have two real roots.
Negative, two complex roots.
Zero, one real root.

anonymous · Answer

soo.. do it like uhh 5^2-4(1)(6)=0??

mertsj · Answer

yes

anonymous · Answer

well what about 3x^2-5x+6=0....the answers given isnt what i came up with so i know ive done something wrong just done know what....i got -97

mertsj · Answer

The problem said to find the number and type of roots.

mertsj · Answer

What did you get for b ^2-4ac?

anonymous · Answer

D=1

anonymous · Answer

which is was one of the answer choices and also two rational roots

mertsj · Answer

yes.  And 1 is positive
If it's positive, then you have two real roots. 
Negative, two complex roots. 
Zero, one real root.

anonymous · Answer

well got them right but the other 3 idk what im doing wrong,  6x^2-x-12=0

mertsj · Answer

What is b^2-4ac for that problem?

anonymous · Answer

x^2-4(6)(12) right?

mertsj · Answer

Looks to me like the 12 is negative.

anonymous · Answer

yea sorry forgot to say that but i got 288 which aint one of my choices D=289, two irrational roots or D=289 two rational roots

mertsj · Answer

1^1-4(6)(-12)=1+288=289

anonymous · Answer

ooo so i have to put 1 i cant just keep x

mertsj · Answer

|dw:1381456377186:dw|