Question

How do I find the period for f(x)=cot(5x+5)+5 ? I thought it was 2pi/5, but apparently its wrong, can someone please explain ?

Answer 1

\[a+b\cos(k(t-c))
\\period = \frac{2\pi}{k}\]

Answer 2

factor the 5 out of 5x+5
then we have 5(x+1)
period = 2pi/k
k=5

Answer 3

so, if you have this form
\[a+b\cos(kt-kc))
\]then you need to factor the k out to get
\[a+b\cos(k(t-c))
\]

if you have this form
\[a+b\cos(kt)
\] this is just a special case of the other one, but c = 0
so in this situation we still hve period = 2pi/k

Answer 4

understand @dnova21 ?

Answer 5

Yes, thank you !

Answer 6

you dont have to factor the k out. either way its the same thing for period.

Answer 7

Oh okay :)

Answer 8

cot≠cos

Answer 9

Ah I just caught that :S I found the answer to be pi/5 nonetheless, so when you are working with cot you do pi/B instead of 2pi/b right ?

Answer 10

yes , because tan(x), and cot(x) have a period of π,

Answer 11

Oh now I get it thanks for clarifying :)

Answer 12

sorry i read wrong