Show that if R is ring with unit element and 1=0,then R=(0)
Let \(r\in R\). It can be proved that \(0\cdot r=0\) (usually available in the text book). Isnce \(1=0\) then \[r=1\cdot r=0\cdot r=0\] Therefore \(R=\{0\}\).
Hello
Can you explain more please
which part that you don't understand?
you divide 0/Cdot
that is just multiplication in the ring
what about if I said if 0=1 , a0=a that means 0=1
yes, if 0=1 the statement a0=a is a correct statement
that means I can answer it like this
like what? what did you show there?
if I said 0a=a
so what if you show that 0a=a?
i ask you if that correct if i said 0a=a is that mean 0=1?
no, you said that if 1=0 is it correct that a0=0 and 1=0? So I said yes
so my question is that means i have to suppose that a=1
no. In the beginning we don't suppose anything about a. We just take any \(a\in R\). Next we use the property of the unity element 1. So \(a=1a\). But it is given that 1=0, so we can replace teh 1 with 0. Therefore we have \[ a=1a=0a \] But 0a=0. Therefore a=0
thank you
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