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Mathematics 14 Online
OpenStudy (anonymous):

=

OpenStudy (anonymous):

is it like this ? \[\sec^-1 [-\sqrt{3}/3\]

OpenStudy (anonymous):

the there is ] at the very end

OpenStudy (anonymous):

no, sec^-1[-1 sq rt 3 / sq rt 3]

OpenStudy (anonymous):

like this ? \[\sec^-1[-\sqrt{3}/\sqrt{3}]\]

OpenStudy (anonymous):

theres a -1 infront of the first sq rt 3

OpenStudy (anonymous):

like this \[\sec−1[−1(\sqrt{3}/\sqrt{3})]\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

oki bro let me tell those equations are just same.. only we when writing '-' sign directly before any term we assume that it is multiplied by -1 so tell me what is \[\sqrt{3}/\sqrt{3}\] ??

OpenStudy (anonymous):

-1...?

OpenStudy (anonymous):

so pi is the answer?

OpenStudy (anonymous):

yep you are right .. !!

OpenStudy (anonymous):

what if its sec^-1[-2/sq rt 3/ 3] then?

OpenStudy (anonymous):

like this?? \[\sec^-1[-2(\sqrt{3}/\sqrt{3})]\]

OpenStudy (anonymous):

yea, just curious

OpenStudy (anonymous):

id appreciate another example :)

OpenStudy (anonymous):

same drill bro as we know \[\sqrt{3}/\sqrt{3}\] we can write given equation as \[\sec^-1[(-2)\times1]=\sec^-1(-2)=2pie/3\]

OpenStudy (anonymous):

oh ok cool ty

OpenStudy (anonymous):

your welcome ;)

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