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OpenStudy (anonymous):
is it like this ?
\[\sec^-1 [-\sqrt{3}/3\]
OpenStudy (anonymous):
the there is ] at the very end
OpenStudy (anonymous):
no, sec^-1[-1 sq rt 3 / sq rt 3]
OpenStudy (anonymous):
like this ?
\[\sec^-1[-\sqrt{3}/\sqrt{3}]\]
OpenStudy (anonymous):
theres a -1 infront of the first sq rt 3
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OpenStudy (anonymous):
like this
\[\sec−1[−1(\sqrt{3}/\sqrt{3})]\]
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
oki bro let me tell those equations are just same..
only we when writing '-' sign directly before any term
we assume that it is multiplied by -1
so tell me what is
\[\sqrt{3}/\sqrt{3}\] ??
OpenStudy (anonymous):
-1...?
OpenStudy (anonymous):
so pi is the answer?
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OpenStudy (anonymous):
yep you are right .. !!
OpenStudy (anonymous):
what if its sec^-1[-2/sq rt 3/ 3] then?
OpenStudy (anonymous):
like this?? \[\sec^-1[-2(\sqrt{3}/\sqrt{3})]\]
OpenStudy (anonymous):
yea, just curious
OpenStudy (anonymous):
id appreciate another example :)
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OpenStudy (anonymous):
same drill bro as we know
\[\sqrt{3}/\sqrt{3}\]
we can write given equation as
\[\sec^-1[(-2)\times1]=\sec^-1(-2)=2pie/3\]