Question

Anti derivative of sec^2(theta/2)

Answer 1

\[\sec^2(\theta/2)\] How does this anti derivative = 2tan(theta/2), don't understand the "2" in the front part.

Answer 2

You're letting u = theta/2
u = theta/2
du = (1/2)dtheta
dtheta = du/(1/2) = simply 2du

\[\int\limits_{}^{}\sec^{2}(\theta /2)d \theta = \int\limits_{}^{}\sec^{2}u(2du)\]

Answer 3

Ahh, nice, thanks Psymon :P, just stressing myself out, midterm tomorrow :X.

Answer 4

So ive heard, lol.