Question

what is the domain of g(x)= square root of x + 1?

Answer 1

Do you mean \[g(x) = \sqrt{x+1}\] ?
(I love how you can make all the fancy math symbols on this thing)

Answer 2

yes, i just can't figure out how to make the math symbols on here.

Answer 3

\(\ddot \smile\)

Answer 4

Click the little "Equation" button

Answer 5

\[g(x)=\sqrt{x+1}\]
domain of a function means the range of x that can be taken.
by looking at this function, we notice that RHS of the equal sign, there's a square root.
now in order to make this square root meaningful, x+1 must satisfy the condition that x+1>= 0

Answer 6

so it would be all real numbers greater than zero right?

Answer 7

no. it must satisfy X + 1 >= 0.
you have to solve this inequality for the range of x.
x + 1 >= 0
x >= -1
so domain of this is any number that bigger or equal to -1

Answer 8

thanks again!

Answer 9

no worries