what pair of triangles can be proven congruent by sas
I believe it's right triangles
thats wt the question says
I think it's G, H and I?
it would be G because It has two sides that are even with an angle between them
F seems to use the SSS axiom.
I forgot, do triangles NEED to be right-angled for these axioms?
not always
So each of them except F seem to have the the same angle and same two sides.
If you disagree, why do you disagree?
@mathman806
If you look closely the sas axioms need to be two equal sides that share an equal angle on two triangles. F has three equal sides so therefore it's out H has ssa so therefore that one cannot be it I only has one side and one angle given that are equal so we cannot prove that the triangle are equal so the only one remaining is G
@s3a
@s3a
Two secs. I'm helping multiple people at time, that's why I'm slow.
Okay so, I see how H is out in addition to F.
What's I? Isn't that SAS too?
nope it only gives us a side and an angle to work with we need one more piece of information before we can give it an axiom
Oh! Silly me, I was assuming that the two sides that are close to each other were equal! I get it now! Thanks, @mathman806. :D @javo22, do you get that G is the answer?
yea
Alright, good. :)
no problem @s3a
:)
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