Question

In fruit flies, the gene for red eyes (R) is dominant and the gene for sepia eyes (r) is recessive. If a red-eyed homozygous fly (RR) and a red-eyed heterozygous fly (Rr) mate together, what are the possible genotypes of their offspring?

Answer 1

RR, Rr, and rr.

Answer 2

Another questions?

Answer 3

If a pea plant has a genotype SSTt, what are the possible genetic combinations that could be present in a single grain of pollen produced by the plant?

SS, Tt, ST

ST, St, st

SS, Tt, ST, St

ST, St

Answer 4

Oh is it that test? [1] Ff
[2] RR, Rr, and rr.
[3] 25% tall, 50% intermediate, 25% short.
[4] ST, St.
[5] 75%.
[6] His mother’s father also exhibited the trait. (Not sure about this answer).
[7] It will not affect the length of the tails of any of the offspring.

Answer 5

thank you thank you thank you

Answer 6

Maybe different but if I am right its a test I took so those may be the answers but just in case ask them anyway.

Answer 7

1. Which of the following genotypes is homozygous dominant?
tt
Ff
SS
XY

2.In fruit flies, the gene for red eyes (R) is dominant and the gene for sepia eyes (r) is recessive. If two red-eyed heterozygous flies (Rr) mate together, what are the possible genotypes of their offspring? (Hint: You many want to complete a Punnett square.)

Rr only
RR and Rr
RR and rr
RR, Rr, and rr

3.In a monohybrid cross, if the gene for tall (T) plants was incompletely dominant over the gene for short (t) plants, what would be the predicted result of crossing an intermediate (Tt) plant with a tall (TT) plant? (Hint: You may want to complete a Punnett square)

25% tall, 50% intermediate, 25% short
50% tall, 50% intermediate
50% tall, 25% intermediate, 25% short
100% intermediate

4. If a pea plant has a genotype SSTt, what are the possible genetic combinations that could be present in a single grain of pollen produced by the plant?

ST, St
SS, Tt, ST
ST, St, st
SS, Tt, ST, St

5. The allele for a widow’s peak has complete dominance over the allele for a straight hairline (w). What is the probability of two parents heterogeneous for a widow’s peak (Ww) having an offspring with a widow’s peak?

0%
25%
50%
75%

6. If a baby boy inherits a recessive allele from his mother, in which of the following circumstances would he most likely exhibit that recessive trait?

He inherited the dominant trait from his father.
His mother’s father also exhibited the trait.
The allele is X-linked.
The allele skips a generation.

7. A mouse’s tail gets cut off. If the mouse has babies later, how will this affect the length of the tails of its offspring?

It will affect the length of the tails of all the offspring.
It will affect the length of the tails of some of the offspring.
It will not affect the length of the tails of any of the offspring.
It depends on the length of the mate’s tail.

Answer 8

Those your questions?

Answer 9

yea that's most of them i think like 3 are different

Answer 10

Ohh ok which ones? I was just digging that out of a folder so I may not able and answer the others this fast.

Answer 11

What are the genotypes of the parents in the monohybrid cross below if the following offspring genotypes are predicted?




?

?

?

TT

Tt



?

Tt

tt



Tt and Tt

TT and tt

Tt and TT

Tt and tt

Answer 12

>_< mind just died as I looked at that... hmmmm give me a few.

Answer 13

3.In a monohybrid cross, if the gene for tall (T) plants was incompletely dominant over the gene for short (t) plants, what would be the predicted result of crossing an intermediate (Tt) plant with a tall (TT) plant? (Hint: You may want to complete a Punnett square)

25% tall, 50% intermediate, 25% short
50% tall, 50% intermediate
50% tall, 25% intermediate, 25% short
100% intermediate

This isn't the same as that one?

Answer 14

hmmm they look a lot a like.

Answer 15

in guinea pigs, dark hair (D) is dominant over light hair (d) and curly hair (C) is dominant over smooth hair (c). Complete a dihybrid cross for parents with the genotypes: DdCc × DdCc and answer the following in complete sentences.

Describe how you would set up a Punnett square for this cross.
List the likelihood of each possible offspring genotype.
List the likelihood of each possible offspring phenotype.

Answer 16

I'm not good at describing those type of answers.... I am best a multi-choice. Hmmmm I don't know if I will be much help with that question, Sorry.

Answer 17

A man and woman have a son who is color blind, a recessive sex-linked trait carried on the X-chromosome, but neither parent is color blind. The woman is now pregnant with their second child. Which of the following statements is true about the second child?

A daughter will be color blind because the father is a carrier of the recessive allele.

A son will be color blind because the mother is a carrier of the recessive allele.

A daughter will not be color blind because the father is not a carrier of the recessive allele.

A son will be color blind because the father’s mother must have been a carrier for recessive allele

Answer 18

http://bit.ly/PVqgcu That is the punnet square you want, just change the letters around.

Genotypes are the "genes" of the offspring, while phenotypes are the "ph"ysical characteristics.

Genotypes:
DDCC (1/16) - Dark Curly
DDCc (2/16) - Dark Curly
DdCC (2/16) - Dark Curly
DdCc (4/16) - Dark Curly
DDcc (1/16) - Dark Smooth
Ddcc (2/16) - Dark Smooth
ddCC (1/16) - Light Curly
ddCc (2/16) - Light Curly
ddcc (1/16) - Light Smooth

You can figure out the phenotypes, just add the fractions of the same physical features together

Answer 19

Thats to the pig one.

Answer 20

A daughter will be color blind because the father is a carrier of the recessive allele.

Answer 21

thank you

Answer 22

No problemo.

Answer 23

When you finish with a question don't forget to close it. =)