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OpenStudy (luigi0210):
\[\LARGE (\frac{a}{b})^{-x}=(\frac{b}{a})^{x}\]
OpenStudy (anonymous):
so i make the 9 into a frction like \[\frac{ 9 }{ 1 }\] then flip it?
OpenStudy (luigi0210):
Yup!
OpenStudy (anonymous):
ok then what would i do with the -2/1 exponent?
OpenStudy (anonymous):
i meant 2/3
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OpenStudy (luigi0210):
When you flip the fraction, it just becomes positive.
OpenStudy (anonymous):
would i multiply it with 9/1?
OpenStudy (luigi0210):
It goes like this:
First you flip the number to make the exponent positive
\[\LARGE 27^{-2/3}=(\frac{1}{27})^{2/3}\]
Now just distribute the exponent out to everything:
\[\LARGE a^{2/3}=\sqrt[3]{x^2}\]
OpenStudy (anonymous):
but how would i get it to one of my answer choices
OpenStudy (luigi0210):
So what's 1^(2/3) and 27^(2/3)?
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OpenStudy (anonymous):
1^(2/3) is \[^{3}\sqrt{1^{2}}\] and the other is \[^{3}\sqrt{27^{2}}\]
OpenStudy (luigi0210):
Correct, now simplify them
OpenStudy (anonymous):
how would i do that
OpenStudy (luigi0210):
Well 1 to any power 1. So that one is simple. For the 27, first take the cubic root of it.
OpenStudy (anonymous):
so i square it then divide it by 3?im not sure how to do tht
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OpenStudy (luigi0210):
Hmm, do you have a calculator?
OpenStudy (anonymous):
yea it is on my computer.i have it up right now
OpenStudy (luigi0210):
Okay, type this in: 27^(1/3)
OpenStudy (anonymous):
i got it.it is 3
OpenStudy (luigi0210):
Since \[\LARGE 27^{2/3}=27^{1/3*(2)}\]
Right, now sqaure that and you get..
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OpenStudy (luigi0210):
*square
OpenStudy (anonymous):
i get 9
OpenStudy (luigi0210):
Correct!
So our final answer is:
\[\LARGE \frac{1}{9}\]
OpenStudy (anonymous):
thank you so much i really apreciate it
OpenStudy (luigi0210):
ANytime bud.
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