The decay of 230 mg of an isotope is described by the function A(t)= 230e-0.031t, where t is time in years. Find the amount left after 26 years. Round your answer to the nearest mg. Show all of your work for full credit.
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OpenStudy (homeworksucks):
Just plug in 26?
OpenStudy (anonymous):
for t?
OpenStudy (homeworksucks):
yup
OpenStudy (anonymous):
what about for e?
is that the natural base?
OpenStudy (homeworksucks):
I think so, I think e is just the constant
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OpenStudy (anonymous):
okay so i plugged it in and got 230e-0.806
OpenStudy (anonymous):
actually the problem didn't copy right it should be 230e^-0.806
OpenStudy (homeworksucks):
Oh, yeah, still plug it in though
OpenStudy (anonymous):
what do i do after that?
OpenStudy (homeworksucks):
Find e to the -0.806th power, and times it by 230
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OpenStudy (anonymous):
And then you party like a rock star
OpenStudy (homeworksucks):
Did you get 103 mg?
OpenStudy (anonymous):
okay so now i have e=2.71828
230(2.71828)^-0.806
625.2044^-0.806
OpenStudy (anonymous):
how in the world did you get 103....?
OpenStudy (anonymous):
@Homeworksucks
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OpenStudy (homeworksucks):
Oh umm BEDMAS
OpenStudy (homeworksucks):
230 (e^-0.806)
OpenStudy (anonymous):
e=2.71828
OpenStudy (anonymous):
so would it be 2.71828^-0.806?
OpenStudy (homeworksucks):
yup, times 230
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OpenStudy (anonymous):
i'm confused about how you have -0.806 as an exponent though...how would you multiply that out?
OpenStudy (homeworksucks):
e^-0.806 is 0.4466410621, times that by 230
OpenStudy (anonymous):
how did you figure that out though?
OpenStudy (homeworksucks):
It goes exponents then Multiplication, according to BEDMAS(or PEMDAS)
OpenStudy (anonymous):
....i've never learned how to multiply an exponent that is negative and a decimal though. that's what i'm still confused about. i know how to do pemdas (:
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