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Mathematics 19 Online
OpenStudy (anonymous):

The decay of 230 mg of an isotope is described by the function A(t)= 230e-0.031t, where t is time in years. Find the amount left after 26 years. Round your answer to the nearest mg. Show all of your work for full credit.

OpenStudy (homeworksucks):

Just plug in 26?

OpenStudy (anonymous):

for t?

OpenStudy (homeworksucks):

yup

OpenStudy (anonymous):

what about for e? is that the natural base?

OpenStudy (homeworksucks):

I think so, I think e is just the constant

OpenStudy (anonymous):

okay so i plugged it in and got 230e-0.806

OpenStudy (anonymous):

actually the problem didn't copy right it should be 230e^-0.806

OpenStudy (homeworksucks):

Oh, yeah, still plug it in though

OpenStudy (anonymous):

what do i do after that?

OpenStudy (homeworksucks):

Find e to the -0.806th power, and times it by 230

OpenStudy (anonymous):

And then you party like a rock star

OpenStudy (homeworksucks):

Did you get 103 mg?

OpenStudy (anonymous):

okay so now i have e=2.71828 230(2.71828)^-0.806 625.2044^-0.806

OpenStudy (anonymous):

how in the world did you get 103....?

OpenStudy (anonymous):

@Homeworksucks

OpenStudy (homeworksucks):

Oh umm BEDMAS

OpenStudy (homeworksucks):

230 (e^-0.806)

OpenStudy (anonymous):

e=2.71828

OpenStudy (anonymous):

so would it be 2.71828^-0.806?

OpenStudy (homeworksucks):

yup, times 230

OpenStudy (anonymous):

i'm confused about how you have -0.806 as an exponent though...how would you multiply that out?

OpenStudy (homeworksucks):

e^-0.806 is 0.4466410621, times that by 230

OpenStudy (anonymous):

how did you figure that out though?

OpenStudy (homeworksucks):

It goes exponents then Multiplication, according to BEDMAS(or PEMDAS)

OpenStudy (anonymous):

....i've never learned how to multiply an exponent that is negative and a decimal though. that's what i'm still confused about. i know how to do pemdas (:

OpenStudy (anonymous):

i appreciate your help by the way (:

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