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Mathematics 17 Online
OpenStudy (anonymous):

Can someone explain how.. typing problem.

OpenStudy (anonymous):

\[\frac{ (n+1)^{n+1} }{ (n+1)! } * \frac{ n! }{ n ^{n} } = \frac{ (n+1) }{ n ^{n} }\]

OpenStudy (anonymous):

I forgot factorials.

OpenStudy (anonymous):

I know its a simple concept. I just need an explanation please.

OpenStudy (anonymous):

woops. it is = (n+1)^n / n^n

OpenStudy (watchmath):

The simplified expression should be \[\left(\frac{n+1}{n}\right)^n\]

OpenStudy (anonymous):

yes

OpenStudy (watchmath):

Just notice that \((n+1)!=n!(n+1)\)

OpenStudy (anonymous):

I still cannot grasp it.. lol idk why.

OpenStudy (anonymous):

5! = 5 * 4 * 3 * 2 * 1 so n! = n!(n-1)

OpenStudy (watchmath):

can you cancel anything?

OpenStudy (anonymous):

You cancel the n!(n+1) right?

OpenStudy (watchmath):

yes, so what do you have after canceling that?

OpenStudy (anonymous):

(n+1)^n+1 / n^n

OpenStudy (watchmath):

be careful! you cancel one of the n+1 so you have \((n+1)^n\) now

OpenStudy (anonymous):

im sorry.. im trying to understand. lol so n! = n!(n-1) yes?

OpenStudy (watchmath):

no, that is incorrect! In the simplification we don't change the \(n!\) we just rewrite \((n+1)!=n!(n+1)\)

OpenStudy (anonymous):

OHHHHHHHHHHH

OpenStudy (anonymous):

so then (n+1)^n and (n+1) reduces to (n+1)^n

OpenStudy (anonymous):

the n1's cancel out.

OpenStudy (anonymous):

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