Mathematics
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OpenStudy (anonymous):
Can someone explain how..
typing problem.
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OpenStudy (anonymous):
\[\frac{ (n+1)^{n+1} }{ (n+1)! } * \frac{ n! }{ n ^{n} } = \frac{ (n+1) }{ n ^{n} }\]
OpenStudy (anonymous):
I forgot factorials.
OpenStudy (anonymous):
I know its a simple concept. I just need an explanation please.
OpenStudy (anonymous):
woops. it is = (n+1)^n / n^n
OpenStudy (watchmath):
The simplified expression should be \[\left(\frac{n+1}{n}\right)^n\]
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OpenStudy (anonymous):
yes
OpenStudy (watchmath):
Just notice that \((n+1)!=n!(n+1)\)
OpenStudy (anonymous):
I still cannot grasp it.. lol idk why.
OpenStudy (anonymous):
5! = 5 * 4 * 3 * 2 * 1
so n! = n!(n-1)
OpenStudy (watchmath):
can you cancel anything?
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OpenStudy (anonymous):
You cancel the n!(n+1) right?
OpenStudy (watchmath):
yes, so what do you have after canceling that?
OpenStudy (anonymous):
(n+1)^n+1 / n^n
OpenStudy (watchmath):
be careful! you cancel one of the n+1 so you have \((n+1)^n\) now
OpenStudy (anonymous):
im sorry.. im trying to understand. lol
so n! = n!(n-1) yes?
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OpenStudy (watchmath):
no, that is incorrect! In the simplification we don't change the \(n!\) we just rewrite \((n+1)!=n!(n+1)\)
OpenStudy (anonymous):
OHHHHHHHHHHH
OpenStudy (anonymous):
so then (n+1)^n and (n+1) reduces to (n+1)^n
OpenStudy (anonymous):
the n1's cancel out.
OpenStudy (anonymous):
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