Question

how to solve this differentiation sin square x??

Answer 1

\[\sin ^{2} x.. answer this.. pls\]

Answer 2

There is probably some fancy formula.
But you can also just remember that
\[(f(x)g(x))' = f'(x)g(x) + f(x)g'(x)\]
So just derive\[\sin x \sin x\]

Answer 3

Yah product rule is an interesting way to do it I guess :)

So like, make sure you understand the exponent notation for trig functions.\[\Large \sin^2x \quad=\quad (\sin x)^2\]Taking the derivative gives us,\[\Large \left[(\sin x)^2\right]' \quad=\quad 2(\sin x)\color{royalblue}{(\sin x)'}\]We apply the Power Rule to the outer function then we apply the chain rule, multiplying by the derivative of the inner function.
So we need to take the derivative of the blue part.

Answer 4

You can use the product rule, Or the chain rule, Or a trig substitution for this problem