Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

CAN ANYBODY HELP ME WITH Applications: Projectile Motion Math???? Ted throws an object into the air with an initial vertical velocity of 54 feet per second from a platform that is 40 feet above the ground. About how long will it take the object to hit the ground? A. 1 second B. 2 seconds C. 3 seconds D. 4 seconds

OpenStudy (anonymous):

Im horrible at Projectile Motion equations

OpenStudy (anonymous):

I can solve with a given equation, but am not far enough in math to know intuitively what equation to form

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

I know the form but not the values to insert

OpenStudy (psymon):

Are we assuming its shot straightforward and not at an angle? O.o

OpenStudy (anonymous):

Idk

OpenStudy (anonymous):

vertical velocity of 54 feet per second from a platform that is 40 feet above the ground for being descriptive it's vague.

OpenStudy (anonymous):

Its vertical

OpenStudy (psymon):

Oh, straight up then.

OpenStudy (anonymous):

Straight up then how long will it take to get down??

OpenStudy (psymon):

I dont remember any kinematic equations, but im sure you can use one of them. Do you have any kinematic equations from lecture or a text?

OpenStudy (anonymous):

solve for y=-40

OpenStudy (anonymous):

So remember I dont get any of this.

OpenStudy (psymon):

So you werenever given any kinematic equations?

OpenStudy (anonymous):

let me check

OpenStudy (anonymous):

" Use the projectile motion formula for when the height is in feet. Then substitute 0 for h(t), 54 for v0, and 40 for h0. Disregard the negative solution. "

OpenStudy (psymon):

So looks like you should have SOMETHING. There are usually 3 kinematic equations, so looks like you shoudl have one of them somewhere. Ive never been able to remember them personally.

OpenStudy (anonymous):

Dont ask me i just started this stuff

OpenStudy (psymon):

It has nothing to do with how new you are to it, you should have an equation somewhere. You might not know what it is, but you have to have that formula or theresnothign wecan do. If you can find it I can try to help ya.

OpenStudy (anonymous):

kinematics yummmm. Just google up "kinematic equations for projectile motion" it should easy plug and play

OpenStudy (anonymous):

how @OrionsBelt

OpenStudy (anonymous):

how to google? Open a browser and type in google.com lol.

OpenStudy (anonymous):

no i dont see anything in the "kinematic equations for projectile motion" section and @ehuman sry but idk how to use it

OpenStudy (anonymous):

i think its parbola

OpenStudy (anonymous):

http://en.wikipedia.org/wiki/Projectile_motion

OpenStudy (anonymous):

...

OpenStudy (anonymous):

yes it is a parabola even if thrown straight up, that last link has formula for parabola

OpenStudy (anonymous):

@Psymon @ehuman its an The initial velocity type of equation

OpenStudy (anonymous):

The equation is in @ehuman 's link

OpenStudy (psymon):

Still has to do with kinematics. But trust me, if you find the right formula theres not much thought to it. Youre assumign youre clueless too early before you even have the necessary tools.

OpenStudy (anonymous):

@Hero @myininaya can you help us out?

OpenStudy (anonymous):

(sigh) I'll just have to guess......

OpenStudy (unklerhaukus):

what angle does Ted throws the object?

OpenStudy (anonymous):

Vertical...

OpenStudy (unklerhaukus):

up or down?

OpenStudy (anonymous):

Why is this guy standing there throwing junk in the air anyway? Anyway \[-32t^2 + 54t + 40 = 0\] I think

OpenStudy (anonymous):

Up

OpenStudy (anonymous):

Lol idk its my question lol

OpenStudy (unklerhaukus):

\[y(t)=y(0)+{v_0}_yt+\tfrac12a_yt^2\]

OpenStudy (anonymous):

so

OpenStudy (unklerhaukus):

y(0) is the initial height , i.e. the height of the platform v_0_y is the vertical component of the initial velocity a is vertical component of acceleration , ie - gravity t is time

OpenStudy (anonymous):

Oh, yeah, half. \[-16t^2 + 54t + 40 = 0\] Who uses feet in kinematics equations, anyway? Probably the same kind of person who stands on platforms throwing stuff in the air.

OpenStudy (primeralph):

|dw:1381558210004:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!