Two cars start moving from the same point. One travels south at 60 miles/hr and the other travels west at 25 miles/hr. At what rate is the car distance between the cars increasing 2 hours later. No calculators, no cheating!! Right answer gets a cookie! Go!
no fair, wio's part calculator, he's like sheldon from BB theory ;D
if wio gets the right answer he'd dq'd
haha
\[ z^2=x^2+y^2 \]So \[ 2zz'=2xx'+2yy' \]Dividing by \(2\)\[ zz'=25x+60y\implies z'=\frac{xx'+yy'}{\sqrt{x^2+y^2}{}}=\frac{25x+60y}{\sqrt{x^2+y^2}{}} \]
We can use \(x=25\times 2=50\) and \(y=60\times 2=120\).
It's not going to be a rational number.
it is
\(2500+14400=16900 = 130^2\)?
Draw a picture wio!
Ok
WIO ! WAY TO GO! I'LL BE CHEERING YOU ON ! YOU COULD DO THIS !! I WISH I COULD GIVE YOU 10 MEDALS! CUZ I WOULD. WIO SWEETIE YOU WILL GET THE ANSWER!
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yes
WIO! WIO! WIO! WIO! BEST HELPER IN HERE! WIO WIO. OH MY WIO. WIO I LOVE YOU.
WIO YOU ARE SIMPLY. AWESOME.
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PRIME BACK OFF. WIO GOT THIS.
L is here have no fear!
\[ z'=\frac{1250+7200}{130}=\frac{845}{13} \]
Wio wins!
\[ z'=65 \]
WIO, YOUR BABYGIRL HIS HERE. YOU COULD DO IT
*IS
Let variable x be the distance car A travels in t hours, and variable y the distance car B travels in t hours. Let variable L be the distance between cars A and B after t hours.
GET OUT SHAM! MY BOO WIO DID IT !
60 - 25 = 35 so the equation for L would be L = √x^2 + (35-y)^2
Well done @wio ^.^
GOOOOOOOOOOOOOOOOOOOALLL ! WIO ACTUALLY DID IT! EVERYONE SHOULD GIVE HIM A MEDAL!
Poor @wio
EVERY. SINGLE. PERSON SEEING THIS. NEED. TO. GIVE HIM. A. MEDAL.
Other people need help. Get to it.
well since the rate is after two hours it would be the same as x = 50t and y = 120t
PRIME YOU DID AMAZING TOO. CONGRATS!
@timaashorty Are you new here?
hahahahha prime
NOPE (:
L = √x^2 + ( 70 - y)^2
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