Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

.

OpenStudy (anonymous):

erp, sorry. Should be y = 5 - x 5 = y + x 5 - x = y y = 5 - x

OpenStudy (anonymous):

ignore that for a sec, sorry. I'll repost it in a sec. To solve that, you plug the value for y into that other equation y = 5 - x y = 1/3 x + 3 therefore 5 - x = 1/3 x + 3

OpenStudy (anonymous):

you solve for x. 1/3 x + x = 5 - 3

OpenStudy (anonymous):

So there you factor out the x, then divide to get x by itself x ( 1/3 + 1 ) = 5 - 3 x = (5-3) / (1/3 + 1)

OpenStudy (anonymous):

so there, you can make it easier by putting the 1 in fraction form with a 3 on the bottom to add to the 1/3 1 = 1/1 = 3/3 \[\frac{ 3 }{ 3 } + \frac{ 1 }{ 3 } = \frac{ 3 + 1 }{ 3 }\]

OpenStudy (anonymous):

Then \[\frac{ 5 - 3 }{ \frac{ 1 + 3 }{ 3} } = \frac{ (5 - 3) 3 }{ 1+3 }\]

OpenStudy (anonymous):

I gotta run, plus I think I'm complicating things. Sorry. To get the solution, you have to solve the two inequalities (I found it easier to do the opposite of what I just showed, and solve for x ----> x ≤ 5 - y Then put in into the other inequality (So where it says x, just put that 5 - y in) Then that should give you the other two vertices you don't know (The first two are x ≥ 0 and y ≥ 0). Then, find the biggest value of x and y allowed within the region (remember that x + y has to be smaller than or equal to 5 given the last constraint), and then put those numbers into C = 6x - 4y to solve for C. You want C as big as it can be. Anyway, good luck, and I can delete all of this convoluted mess if you want :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!