Find the vertex of the graph of the function.
f(x) = 2x^2 - 8x + 6

Question

Find the vertex of the graph of the function.
f(x) = 2x^2 - 8x + 6

anonymous · Answer

(-2,2) ?

***[isuru]*** · Answer

hi,
       this equation is in the slandered form...
    u can convert it to the vertex form using completing squares...
              f(x) = 2x^2 - 8x + 6
                    = 2[ x^2 - 4x + 3]
                    = 2[ (x -2) ^2  -1 ]

now the function is in the vertex form...
            so.... the  co-ordinates of the vertex is..
                       (2 , -2)

so... what is the vertex then ?

anonymous · Answer

vertex is -b/2a
which is 8/4
plug the 2 in to original formula to find the y value at x of 2

anonymous · Answer

no need to complete the square if you have standard form eh?

anonymous · Answer

( 2, -2)

 ( 3, -1)

 ( -1, 3)

 ( -2, 2)

***[isuru]*** · Answer

but u have to learn the basic if u want to go to easy methods...

anonymous · Answer

(2,-2)

***[isuru]*** · Answer

first one is the answer...

anonymous · Answer

Okay thank youu (:

***[isuru]*** · Answer

u r welcome!!

anonymous · Answer

if she is at the point of finding the vertex, they already taught completing the square and quadratic function

anonymous · Answer

so it is time for the shortcut

anonymous · Answer

it is a derivative of the quadratic function

***[isuru]*** · Answer

i know bro...
    but this one was really easy.... 
 so.. a person who knows quadratics won;t asks help for a problem like this.... that's y I used completing square...

anonymous · Answer

you may have a point

***[isuru]*** · Answer

nway ur contribution should also appreciated bro :)