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Chemistry 18 Online
OpenStudy (anonymous):

how can i do this? A solution is prepared by adding 8*10^-4 moles ammonium nitrite (NH4NO2) to form one liter of solution (for Ka = 10^-9.3 for NH4OH and Ka = 10^-4.5 for in HNO2).Analytically find the concentration of each component.

OpenStudy (aaronq):

When you place ammonium nitrite in water it will dissociate, like this: \(NH_4(NO_2)\rightarrow \color{green}{NH_4^+} + \color{blue}{NO_2^-}\) Each one will each with water differently: \(\color{green}{ NH_4^+ +2H_2O \rightarrow NH_4(OH) + H_3O^+}\) \(\color{blue}{ NO_2^- +H_3O^+ \rightarrow HNO_2 +H_2O}\) use equilibrium expressions to find the concentrations. NOTE: the Ka values given are for the production of \(H_3O^+\), and it may not be for the reaction written but the backwards reaction.

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