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Explain why lim x->∞ (cos(x)) does not exist, but lim x->∞ ((cos(x))/(x)) does exist.
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To have a defined limit, a function has to approach a value. When happens when lim x-> inf cos x?
it oscillates...
exactly, between 1 and -1. So it never tends toward a value. But what if there's an x on the bottom?
the limit equals 0?
yah! Even though cos x oscillates between 1 and -1, both of those values are forced to tend towards zero because of the 1/x.
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okay, thank you :)
welcome :) That approach is called the squeeze theorem.
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