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Mathematics 7 Online
jigglypuff314 (jigglypuff314):

Explain why lim x->∞ (cos(x)) does not exist, but lim x->∞ ((cos(x))/(x)) does exist.

OpenStudy (anonymous):

To have a defined limit, a function has to approach a value. When happens when lim x-> inf cos x?

jigglypuff314 (jigglypuff314):

it oscillates...

OpenStudy (anonymous):

exactly, between 1 and -1. So it never tends toward a value. But what if there's an x on the bottom?

jigglypuff314 (jigglypuff314):

the limit equals 0?

OpenStudy (anonymous):

yah! Even though cos x oscillates between 1 and -1, both of those values are forced to tend towards zero because of the 1/x.

jigglypuff314 (jigglypuff314):

okay, thank you :)

OpenStudy (anonymous):

welcome :) That approach is called the squeeze theorem.

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