Question

6z +4 - 2z is greater than or equal to 3z - (5 + z)

Answer 1

This is almost identical to the last problem I showed you. If you understand the last problem, you should be able to do this problem. If you cant do this problem, then redo the last problem.

Answer 2

wouldn't you distribute first

Answer 3

yes, you would distribute first, then reduce, then simplify

Answer 4

im confused

Answer 5

do you subtract 2z from 6z

Answer 6

yes

Answer 7

\[6z+4-2z \ge 3z-(5+z) \rightarrow 6z+4-2z \ge 3z-5-z\] then
\[6z+4-2z \ge 3z-5-z \rightarrow 4z + 4 \ge 2z - 5\]

Answer 8

shouldn't you end up with 4z +4 is greater than or equal to 1z - (5 + z )

Answer 9

no?

Answer 10

i did something wrong

Answer 11

6z+4−2z≥3z−(5+z) → 6z+4−2z≥3z−5−z
6z+4−2z≥3z−5−z → 4z+4≥2z−5

Answer 12

6z + 4 - 2z >= 3z - (5 +z) -- distribute through the parenthesis
6z + 4 - 2z >= 3z - 5 - z -- combine like terms
4z + 4 >= 2z - 5 -- subtract 2z from both sides
4z - 2z + 4 >= -5 -- subtract 4 from both sides
2z >= -5 -4
2z >= -9
z >= -9/2

Answer 13

Thank you

Answer 14

anytime :)