Question

Help please. The combustion of pentane, C5H12, occurs via the reaction
C5H12(g)+8O2(g)→5CO2(g)+6H2O(g)
with heat of formation values given by the following table:
Substance ΔH∘f
(kJ/mol)
C5H12(g) −35.1
CO2(g) −393.5
H2O(g) −241.8

I have tried [(6)(-241.8)+(5)(-393.5)]-[-35.1] =-481.6 but not sure if it is correct?

Answer 1

the set up is good, but i don't think you multiplied everything throughout.

Answer 2

okay thank u

Answer 3

no problem