Question

HELP! I though I got it right but it isn't a choice!
which factor would you cancel from the numerator and denominator to simplify x^2-3x-4 over x^2-16

Answer 1

Did you factor the numerator?

Answer 2

I had thought it was x^2

Answer 3

but it isn't a chioce

Answer 4

Do you know what factors are?

Answer 5

ya...

Answer 6

So how can you think that x^2 is the factors of the numerator?

Answer 7

If I tell you that the factors of 12 are 10 and 7, what would you say?

Answer 8

cause its the same on the num. and the dem

Answer 9

that isn't correct

Answer 10

Exactly, because 10 x 7 is not 12

Answer 11

So when you write factors, they must multiply back to give the original expression. So your first job in this problem is to find the factors of the numerator and then find the factors of the denominator.

Answer 12

x^2 is not a factor. Factors are things that you multiply.

Answer 13

so for 3 would factors be 1? and oohh I see

Answer 14

\[x^2-3x-4=(x-4)(x+1)\]

Answer 15

\[x^2-16=(x-4)(x+4)\]

Answer 16

so would it be x-4?

Answer 17

for the anwser

Answer 18

Yes. And you had better learn to factor or you cannot go much further in math.

Answer 19

4 sqrt 13+ sqrt 6-7 sqrt 13.. could you help me with this?

Answer 20

Let me see if I know what the problem is:

Answer 21

and yes I know...I do know how to factor I have a 97 in the FLVS class I was just having a brain fart.. sorry for making you do all this work but u are helping me

Answer 22

\[4\sqrt{13}+\sqrt{6}-7\sqrt{13}\]

Answer 23

Is that the problem?

Answer 24

yes that's right equation! :)

Answer 25

It is not an equation since there is no equal sign. It is an expression.
Do you know what similar radicals are?

Answer 26

haha ya ik! and yes I do... I learned that in module 10 9.01 in FLVS

Answer 27

or maybe 9.02 not sure

Answer 28

Only similar radicals can be added and you add them by adding the coefficients.

Answer 29

ok so would the answer be -3 sqrt 6?

Answer 30

The two radicals that are similar are the first one and the last one.

Answer 31

or wait -3 sqrt 13 + sqrt 6

Answer 32

\[4\sqrt{13}+\sqrt{6}-7\sqrt{13}=4\sqrt{13}-7\sqrt{13}+\sqrt{6}=\sqrt{13}(4-7)+\sqrt{6}=-3\sqrt{13}+\sqrt{6}\]

Answer 33

yes

Answer 34

so the answer -3 sqrt 13 + sqrt 6

Answer 35

yes

Answer 36

ok! thank you very much u have no idea how much u helped me!

Answer 37

help?

Answer 38

on: 4x-12 over 3x-9

Answer 39

I think the answer is 8 over 3

Answer 40

but I think im wrong

Answer 41

Mertsj ?

Answer 42

help!

Answer 43

Factor 4 from the numerator and factor 3 from the denominator