Question

give the general formula for cos(theta)=-(square root 3)/2. list six solutions

Answer 1

Find the general solution and you can churn out as many solutions as you want.

Answer 2

i understand that theta = -\[\sqrt{3}/2\] at 5pi/6 and 7pi/6
but im stumped from there

Answer 3

Add \(2\pi\)

Answer 4

its asking for 1 formula, but the only way i know how to do it is \[\theta=(5\pi/6 + 2\pi k) \] and \[\theta=(7\pi/6 + 2\pi k ) \] where k is an integer.
how do i make it 1 formula?

Answer 5

Hmmmm, I'm not completely sure.

Answer 6

Usually you can combine answers when they are \(\pi\) away.

Answer 7

thats the prob im having, its a negative so cos can only b neg on Quadrant 2 & 3 so its cant b ...

Answer 8

There isn't a nice way of combining them.

Answer 9

However, if you go halfway between the angles..

Answer 10

You could do this.\[
\frac{(6\pm 1)\pi }{6}+2\pi k
\]

Answer 11

that makes it way cleaner. much appreciated . Semper Fi.