give the general formula for cos(theta)=-(square root 3)/2. list six solutions

Question

anonymous · Answer

Find the general solution and you can churn out as many solutions as you want.

anonymous · Answer

i understand that theta = -$$\sqrt{3}/2$$ at 5pi/6 and 7pi/6
 but im stumped from there

anonymous · Answer

Add $2\pi$

anonymous · Answer

its asking for 1 formula, but the only way i know how to do it is $$\theta=(5\pi/6 + 2\pi k) $$ and $$\theta=(7\pi/6 + 2\pi k ) $$ where k is an integer.
how do i make it 1 formula?

anonymous · Answer

Hmmmm, I'm not completely sure.

anonymous · Answer

Usually you can combine answers when they are $\pi$ away.

anonymous · Answer

thats the prob im having, its a negative so cos can only b neg on Quadrant 2 & 3 so its cant b ...

anonymous · Answer

There isn't a nice way of combining them.

anonymous · Answer

However, if you go halfway between the angles..

anonymous · Answer

You could do this.$$
\frac{(6\pm 1)\pi }{6}+2\pi k
$$

anonymous · Answer

that makes it way cleaner. much appreciated . Semper Fi.