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find the derivative, f(x)=39x+200/x^2.
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help please..
Think of it as \[39x+200x^{-2}\] Does that help?
oh.. is that possible? i think it can help. thanks..
The derivative of 39x is just 39. The derivative of 200x^-2 is -400x^-1 i think i'm probably wrong...
i mean -400x^-3*
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You always subtract 1 from the exponent, even when it's negative.
yeah my bad , accident
39 - 400x^-3 then?..
then?
as in im asking @SACAPUNTAS if that is correct.
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Then you put the negative exponent back into the denominator so your teacher doesn't yell at you for using calculator syntax. But otherwise, yes.
thanks.
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